Ax^2+bx+5=4

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Solution for Ax^2+bx+5=4 equation:


Simplifying
Ax2 + bx + 5 = 4

Reorder the terms:
5 + bx + x2A = 4

Solving
5 + bx + x2A = 4

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + bx + -5 + x2A = 4 + -5

Reorder the terms:
5 + -5 + bx + x2A = 4 + -5

Combine like terms: 5 + -5 = 0
0 + bx + x2A = 4 + -5
bx + x2A = 4 + -5

Combine like terms: 4 + -5 = -1
bx + x2A = -1

Add '-1x2A' to each side of the equation.
bx + x2A + -1x2A = -1 + -1x2A

Combine like terms: x2A + -1x2A = 0
bx + 0 = -1 + -1x2A
bx = -1 + -1x2A

Divide each side by 'x'.
b = -1x-1 + -1xA

Simplifying
b = -1x-1 + -1xA

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